An airplane leaves Los Angeles and travels 5 hours to New York City. The return trip travels along the same route and takes 6 hours and 15 minutes because the plane travels 99 mph slower due to a headwind. Find the distance the plane flies between the two cities.

Respuesta :

The distance the plane flies between the two cities is 2,475 miles.

Given that, an aeroplane leaves Los Angeles and travels 5 hours to New York City. The return trip travels along the same route and takes 6 hours and 15 minutes because the plane travels 99 mph slower due to a headwind.

We need to find the distance the plane flies between the two cities.

How to find the distance with speed and time?

To get the distance, multiply the speed by time. You may see these equations simplified as s=d/t, where s is speed, d is distance, and t is time.

Let the speed of an aeroplane while travelling from Los Angeles to New York City be x.

Then the speed of an aeroplane during the return trip will be x-99.

Now, Distance=Speed × Time

So, x × 5 = (x-99) × 6 1/4

⇒5x=25/4 (x-99)

⇒20x=25x-2475

⇒5x=2475

⇒x=495

The speed of an aeroplane is 495 mph.

Now, the distance = 5x =5 × 495

=2,475 miles

Therefore, the distance the plane flies between the two cities is 2,475 miles.

To learn more about speed, distance and time visit:

https://brainly.com/question/4978052.

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