The distance the plane flies between the two cities is 2,475 miles.
Given that, an aeroplane leaves Los Angeles and travels 5 hours to New York City. The return trip travels along the same route and takes 6 hours and 15 minutes because the plane travels 99 mph slower due to a headwind.
We need to find the distance the plane flies between the two cities.
To get the distance, multiply the speed by time. You may see these equations simplified as s=d/t, where s is speed, d is distance, and t is time.
Let the speed of an aeroplane while travelling from Los Angeles to New York City be x.
Then the speed of an aeroplane during the return trip will be x-99.
Now, Distance=Speed × Time
So, x × 5 = (x-99) × 6 1/4
⇒5x=25/4 (x-99)
⇒20x=25x-2475
⇒5x=2475
⇒x=495
The speed of an aeroplane is 495 mph.
Now, the distance = 5x =5 × 495
=2,475 miles
Therefore, the distance the plane flies between the two cities is 2,475 miles.
To learn more about speed, distance and time visit:
https://brainly.com/question/4978052.
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