The height of the boat floating above the seafloor at high tide is 17.5 feet.
In this question, we have been given a boat which is anchored in the water.
At low tide, the boat is floating 20 feet above the seafloor and is a horizontal distance of 40 feet away from its anchor.
And at high tide, the boat is a horizontal distance of 35 feet away from its anchor.
We need to find the distance the boat floating above the seafloor at high tide.
Consider the following diagram.
Let the boat floating m feet above the seafloor when the boat is a horizontal distance of 35 feet away from its anchor.
Since both the triangle are similar triangles, the corresponding sides must be in proportion.
⇒ 20/40 = m/35
We need to find the value of m.
⇒ 20 × 35 = m × 40
⇒ m = 35 / 2
⇒ m = 17.5 feet
Therefore, the height of the boat floating above the seafloor at high tide is 17.5 feet.
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