Respuesta :
The balanced redox reaction between acidified potassium and iron two chloride is given as ,
5[tex]Fe^{+2}[/tex] + 1 [tex]MnO_{4} ^{- }[/tex] + 8 [tex]H^{+}[/tex]→ 5[tex]Fe^{+3}[/tex] ++ 1 [tex]Mn^{+2 }[/tex] + 4[tex]H_{2} O[/tex]
The reaction is spontaneous
Place these numbers as coefficients in front of the formulas containing those atoms.
[tex]Fe^{+2}[/tex] + [tex]MnO_{4} ^{- }[/tex] → [tex]Fe^{+3}[/tex] + [tex]Mn^{+2 }[/tex]
Balance all remaining atoms other than H and O
[tex]Fe^{+2}[/tex] + [tex]MnO_{4} ^{- }[/tex] → [tex]Fe^{+3}[/tex] + [tex]Mn^{+2 }[/tex]
Balance O.
Add enough H2O molecules to the deficient side to balance O.
We have 4O atoms on the left, so we need 4H2O
on the right.
5[tex]Fe^{+2}[/tex] + 1 [tex]MnO_{4} ^{- }[/tex] + 8 [tex]H^{+}[/tex]→ 5[tex]Fe^{+3}[/tex] + 1 [tex]Mn^{+2 }[/tex] + 4[tex]H_{2} O[/tex]
The reaction is spontaneous when the value of E ° for the reaction is positive .
E ° for [tex]MnO_{4} ^{- }[/tex]/ [tex]Mn^{+2 }[/tex] = 1.74 V
E ° = [tex]Fe^{+3}[/tex]/ [tex]Fe^{+2}[/tex] = 0.75 V
E ° for reaction = 1.74 V - 0.75 V = 0.99 V
Hence , E ° for reaction is positive .
to learn about redox reaction please click here ,
https://brainly.com/question/13293425
#SPJ1
