iron(Fe) has a bcc crystal structure, an atomic radius of 0.124nm, and an atomic weight of 55.85g/mol. what is the theoretical density

Respuesta :

The theoretical density will be 7.8 g/cm³.

What is Atomic Radius?

In a molecule, an atomic radius is equal to half the distance between neighboring atoms of the same element.

When we travel down a group, the atomic radius increases, and when we move in a period from left to right, it decreases. The valence electrons being in the same outermost shell at various times explains this. Moving from left to right, the atomic number rises during the same time interval, increasing the effective nuclear charge. Elemental atomic radius decreases as attractive forces rise.

The given values in the question are :

Radius=0.124 nm and,

Atomic weight=55.85 g/mol

For BCC, Z=2

r=0.124 nm=0.124×[tex]10^{-9}[/tex] m

=0.124×[tex]10^{-9}[/tex]×10² cm

ρ= (Z×M)/a³ N₀

a=4r/√3

=(2×55.85 g.[tex]mol^{-1}[/tex])/(4×0.124×[tex]10^{-7}[/tex]/√3)×6.022×[tex]10^{23}[/tex]

ρ=7.8 g/cm³.

Hence, we get the density as 7.8g/cm³.

To get more information about atomic radius :

https://brainly.com/question/13607061

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