In the figure, m∠AOD=105. If m∠AOB=8x, m∠BOC=7x and m∠COD=6x, what is the value of x?

Answer:
x = 5
Step-by-step explanation:
from the diagram
∠ AOB + ∠ BOC + ∠ COD = ∠ AOD ( substitute values )
8x + 7x + 6x = 105
21x = 105 ( divide both sides by 21 )
x = 5
Answer:
5
Step-by-step explanation:
AOB+BOC+COD=AOD
6x+8x+7x=105
21x=105
x=105÷21
x=5