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Answer:
Option 2, 9<V<1944
Step-by-step explanation:
Part 1
[tex]V=\frac{1}{2}(x)(3x)(6x)=9x^3[/tex]
Part 2
[tex]9(1)^3 < V<9(6)^3 \\ \\ 9<V<1944[/tex]