Respuesta :
A slit of width 0.01 mm has light of wavelength 600 nm passing through it onto a screen 60 cm away. The central maximum will be 7.2 cm .
The central maximum is the brightest central portion of the diffraction pattern. The central maximum is the widest and has the maximum intensity.
The diffraction pattern involves a central bright fringe, also known as the central maxima. Furthermore, central maxima is surrounded by dark and bright lines known as the secondary minima and maxima.
Given
slit width = 0.01 mm = .01 * [tex]10^{-3}[/tex] m
wavelength = 600 nm = 600 * [tex]10^{-9}[/tex] m
distance from screen = 60 cm = 60 * [tex]10^{-2}[/tex] m
width of central maxima = (2 * lambda * D) / d
= 2 * 600 * [tex]10^{-9}[/tex] * 60 * [tex]10^{-2}[/tex] / .01 * [tex]10^{-3}[/tex]
= 7.2 * [tex]10^{2}[/tex] m
To learn more about central maxima here
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