Respuesta :

The major products obtained upon treatment of tert-butyl methyl ether with excess HI gives Tertiary butyl iodide and Methanol.

CH3 – O – C – (CH3)3 + HI → CH3 – OH + (CH3)3– C-I

Tertiary butyl methyl ether + Hydrogen iodideMethanol + Tertiary butyl iodide

Where iodine is attached to the 3 - C atom and -OH is attached to the -CH3 group. The reaction involves protonation of oxygen followed by an unimolecular nucleophilic substitution reaction ([tex]SN_{1}[/tex]).

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[tex]SN_{1}[/tex] reactions are nucleophilic substitutions, involving a nucleophile replacing a leaving group. However: [tex]SN_{1}[/tex] reactions are unimolecular: the rate of this reaction depends only on the concentration of one reactant.

[tex]SN_{1}[/tex] reactions occur mostly with tertiary alkyl halides due to steric reasons.

To learn more about the SN1 mechanism please click on the link https://brainly.com/question/20388585

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