The width of the rectangle using synthetic division is; 5x² + 4x - 6.
What is the width of the rectangle whose area is 5x³+19x²+6x-18?
From the task content; the width of the rectangle whose area and length are as given can be evaluated as follows;
Area = Length × width
Hence, width = Area/length.
Upon division by synthetic polynomial division or long division; the resulting expression for the width of the rectangle is; 5x² + 4x - 6.
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The complete question is -
The area of a rectangle is 5x3+19x2+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle?
