Respuesta :
Answer: D) 31 and 41
Find two possible values for c?
It is given that,
[tex](ax+2)(bx+7)=15x^2 +cx+14\\(ax+2)(bx+7)=abx^2 +7ax+2bx+14=abx^2 +(7a+2b)+14\\[/tex]
On comparing both equations
ab = 15 ------ (1)
7a+2b = c -------(2)
Also, it is given that a + b = 8 --------(3)
From equations (1) and (3) it can be observe that either a or b equal to 3 or 5
Therefore, In equation (2),
When a = 3 and b = 5, then c = 7(3)+2(5) = 21+10 = 31
When a = 5 and b = 3, then c = 7(5)+2(3) = 35+6 = 41
For more about linear equation, refer:
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