Respuesta :
The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.
Given that the population mean, [tex]\mu[/tex] = 90 wpm
The standard deviation of the population ,[tex]\sigma[/tex] = 10
Sample size, n = 12
Sample mean, [tex]\bar x[/tex] = 95
The reading rate of students follows the normal distribution.
Let z = [tex]\frac{\bar x - \mu}{\frac{\sigma}{\sqrt n} }[/tex]
= [tex]\frac{95 - 90}{\frac{10}{\sqrt 12} }[/tex]
= 1.732
Probability that the mean reading exceeds 95 wpm = P([tex]\bar x[/tex] >95)
= P(z>1.732)
= 1- P(z<1.732)
= 0.4582
[The value 0.4582 found from the area under the normal curve using tables].
Learn more about Normal Distribution at https://brainly.com/question/27701525
#SPJ4
