Respuesta :
(a) For 1200 rpm the shaft need to be designed 0.39026 in
(b) For 2400 rpm the shaft need to be designed 0.007430 in
A spinning machine component called a shaft is used to transfer power from one location to another. A tangential force applies the power to the shaft, and the torque (or twisting moment) created within the shaft allows the power to be transferred to other machines connected to the shaft.
For (a) 1200 rpm
τ = 4500 psi
P = 12 hp = 6.6 X 10³ lb.in/s
f = 1200/60 = 20 Hz
T = P/2πf = 6.6 X 10³/2π(20) = 0.05254 X 10³
τ = Tc/J = 2T/πc³
c³ = 2T/πτ = 2(0.0525 X 10³)/π(4500) = 0.00743 in³
c = 0.19513 in
d = 2c = 2 (0.119513) = 0.39026 in
For (b) 2400 rpm
τ = 4500 psi
P = 12 hp = 6.6 X 10³ lb.in/s
f = 2400/60 = 40 Hz
T = P/2πf = 6.6 X 10³/2π(40) = 0.02626 X 10³
τ = Tc/J = 2T/πc³
c³ = 2T/πτ = 2(0.02626 X 10³)/π(4500) = in³
c = 0.003715 in
d = 2c = 2 (0.003715) = 0.007430 in
Learn more about the Shaft designing with the help of the given link:
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