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Pam and Jim are competing in a different food competition. In this competition they are asked
to make 3 dishes. The competition is comprised of cooking three meals; each meal must consist
of the challenge ingredients given to them at the beginning of each round. The first and second
dishes are worth 30% of their final score, and the last dish is worth 40%.
The first two dishes are graded on the following categories: taste, presentation, and creativity.
For the first two dishes, taste is 60% of their score, presentation is 25% of their score, and
creativity is 15% - each category is worth a maximum of 20 points.
The third dish is graded on taste and presentation alone, where taste is 70% of their score for
round 3, and presentation is 30% - each with a 20 point score.
Whoever has the largest score wins $100,000. The table below outlines Jim and Pam’s score for
each round, who won?

Respuesta :

The information in the table illustrates that Pam won the 100000 because the final average of 64.9 points were higher than Jim's 63.9 points.

How to compute the value?

It should be noted that we can calculate their final score by multiplying each of the final scores by 0.60, 0.25, and 0.15 because that's the weight held.

Jim's average will be:

Round 1: 17(0.60) = 10.2

18(0.25) = 4.5

19(0.15) = 2.85

Round 2:

18(0.60) = 10.8

18(0.25) = 4.5

16(0.15) = 2.4

Round 3:

15(0.70) = 10.5

18(0.30) = 5.4

Pam's average:

Round 1: 17(0.60) = 10.2

15(0.25) = 3.75

18(0.15) = 2.7

Round 2:

16(0.60) = 9.6

16(0.25) = 4

18(0.15) = 2.7

Round 3:

19(0.70) = 13.3

19(0.30) = 5.7

Adding all the average gives 51.95 which is then divided by 8 to get 6.49 or 64.9 points.

Therefore, the conclusion is that Pam won the 100000 because the final average of 64.9 points were higher than Jim's 63.9 points.

Learn more about tables on:

brainly.com/question/25630111

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