Considering the values of the digits in the number, we have the the value of the 2 in the left most position is 10 times greater than the value of the other 2 in the number of results.
We start counting the values from the final number, with a value of 1 and multiplying by 10, hence:
Moving one position left, the value of the digit is multiplied by 10, hence the value of the 2 in the left most position is 10 times greater than the value of the other 2 in the number of results.
More can be learned about the values of the digits in a number at brainly.com/question/2041524
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