Hello and Good Morning/Afternoon:
Let's take this problem step-by-step:
Let's see what we are given:
[tex]\hookrightarrow V(r)=\frac{4}{3} \pi r^3[/tex]
Let's see what we need to solve:
- v(2) [tex]\hookrightarrow \text {The number between the parentheses, 2, must be plugged into the r's position}[/tex]
[tex]\hookrightarrow v(2) = \frac{4}{3}\pi* 2^3 = \frac{32}{3} \pi =33.51[/tex]
- v(3/2) [tex]\hookrightarrow \text {The number between the parentheses, 3/2, must be plugged into the r's position}[/tex]
[tex]\hookrightarrow v(\frac{3}{2})=\frac{4}{3}\pi* (\frac{3}{2})^3 =\frac{4}{3}\pi *\frac{27}{8} =\frac{9}{2} \pi =14.14[/tex]
- v(3r) [tex]\hookrightarrow \text {The number between the parentheses, 3r, must be plugged into the r's position}[/tex]
[tex]v(3r)=\frac{4}{3}\pi *(3r)^3 =\frac{4}{3}\pi *27r^3=36\pi *r^3 =113.10r^3[/tex]
Answer:
Hope that helps!
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