please help me find out the correct answer

Beaker A is isotonic to cell A.
Some water is moving in and out of cell A.
Beaker C is hypotonic to cell C.
It is the tendency of water to move from the region of high to the region of low water.
Solutions that are isotonic to cells have the same solute concentration as the sap of the cells.
Solutions that are hypotonic to cells have lower solute concentrations than the sap of the cells.
Solutions that are hypertonic have higher solute concentrations than the sap of the cells.
The sap of cells A, B, and C have 0.9% NaCl. Beaker A has 0.9% NaCl, B has 3% NaCl, and beaker C has only distilled water.
Thus, beaker A is isotonic to cell A, beaker B is hypertonic to cell B, and beaker C is hypotonic to cell C.
The isotonicity of beaker A to cell A means that water would be in dynamic equilibrium between the cell and the beaker.
More on water potentials can be found here: https://brainly.com/question/23855783
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