The value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.
How to determine the dimensions?
The given parameters are:
Base = 5(x+3)
Height = 2(x+9)
Perimeter = 108
The perimeter of a rectangle is
P = 2 *(Base + Height)
So, we have:
2 *(5(x + 3) + 2(x + 9)) = 108
Divide both sides by 2
5(x + 3) + 2(x + 9) = 54
Open the brackets
5x + 15 + 2x + 18 = 54
Evaluate the like terms
7x = 21
Divide by 7
x = 3
Substitute x = 3 in Base = 5(x+3) and Height = 2(x+9)
Base = 5(3+3) = 30
Height = 2(3+9) = 24
Hence, the value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.
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