The another end-point of the line segment is -1 -5i, if its mid-point is at 3 - 2i and one endpoint is 7 + i.
According to the given question.
We have mid-point and endpoint of a line segement.
The mid-point is 3 - 2i.
And the one endpoint is 7 + i.
Let the another mid-point be x + iy .
As we know that the mid-point divides the line segement in two equal parts.
Therefore, the another endpoint of the line segment is given by
3 = (x + 7)/2
⇒ 6 = x + 7
⇒ x = 6 - 7
⇒ x = -1
Similarly, for the imaginary part
-2i = (y + i)/2
⇒ - 4i = y + i
⇒ -4i - i = y
⇒ y = -5i
Hence, the another end-point of the line segment is -1 -5i.
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