The acceleration is 2.5 m/s², the velocity after 4 seconds is 10 m/s,the distance after 4 seconds is 20 m, and the work done by the force would be 400 J
The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
Work Done = Force * Displacement
As given in the problem A mass of 8kg is pulled by a force of 20N along a smooth floor
For calculating acceleration
F = ma
20 = 8a
a = 2.5 m/s²
For calculating velocity
v= u + at
v = 0 + 2.5×4
v = 10 m/s
For calculating distance
v² - u² = 2×a×s
10² - 0²= 2×2.5×S
s = 100/5
s = 20 m
For calculating work done by the force
work done = F ×s
= 20 ×20
= 400 J
Hence, the acceleration is 2.5 m/s², the velocity after 4 seconds is 10 m/s, the distance after 4 seconds is 20 m, and the work done by the force would be 400 J
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