The expected frequency will be 1/2 or 50%.
Monohybrid crossing
First, it is important to note that the no grouse allele is dominant over the grouse allele.
Then, let us assume that no grouse allele is represented by A while the grouse allele will be represented by a.
Thus, a pigeon that is homzygous for the no grouse allele will have the genotype AA. On the other hand, a pigeon that is heterozygous for the trait will have the genotype Aa.
The cross between the 2 pigeons will go as follows:
AA x Aa
AA Aa AA Aa
Homzygous = AA = 50%
Heterozygous = Aa = 50%
Thus, the expected frequency of the homzygous no grouse in the offspring is 1/2 or 50%.
More on monohybrid crossing can be found here: https://brainly.com/question/15314052
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Suppose a pigeon that is homozygous for the no grouse allele mates with a heterozygous pigeon. What is the expected frequency of the homozygous no grouse genotype in the offspring? The no grouse allele is dominant over the grouse allele
