Ivan began to prove the law of sines using the diagram and equations below.

Triangle A B C is shown. A perpendicular bisector is drawn from point C to point D on side B A to form a right angle. The length of the perpendicular bisector is h, the length of C B is a, the length of C A is b, and the length of B A is c.

sin(A) = h/b, so b sin(A) = h.

sin(B) = h/a, so a sin(B) = h.

Therefore, b sin(A) = a sin(B).

Which equation is equivalent to the equation
b sin(A) = a sin(B)?
StartFraction a Over sine (uppercase B) EndFraction = StartFraction b Over sine (uppercase A) EndFraction
StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction
StartFraction sine (uppercase A) Over sine (uppercase B) EndFraction = StartFraction b Over a EndFraction
StartFraction sine (uppercase B) Over a EndFraction = StartFraction sine (uppercase A) Over b EndFraction

The law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

Mathematically, the law of sines is given by this equation:

[tex]\frac{sinA}{a} =\frac{sinB}{b}[/tex]

In this context, we can infer and logically deduce that an equation which is equivalent to the equation bsin(A) = asin(B) is [tex]\frac{sinA}{a} =\frac{sinB}{b}[/tex].

Read more on law of sines here: https://brainly.com/question/7922954

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