4. The polynomial-4.9² +40t +20 represents the distance above the ground of an object thrown straight up from an initial height of 20 meters and with an initial speed of 40 meters per second. How long does it take the object to
reach it's maximum height?
20.000 s
8.636 s
4.082 s
101 6330

Respuesta :

The object represented by h(t) = -4.9t² + 40t + 20 would take 4.082 seconds to reach it's maximum height.

What is an equation?

An equation is an expression that shows the relationship between two numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.

The height (h) is represented by:

h(t) = -4.9t² + 40t + 20

The maximum height is at h'(t) = 0, hence:

h'(t) = -9,8t + 40

-9.8t + 40 = 0

t =  4.082

The object represented by h(t) = -4.9t² + 40t + 20 would take 4.082 seconds to reach it's maximum height.

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