The bearing and distance is from the starting position is 111° and 225.7 miles respectively.
The distance from A to B = 1.4 * 110 = 154 miles
The distance from B to C = 1.5 * 110 = 165 miles
The distance from A to C = x
Using Pythagoras theorem:
x = √(165² + 154²)
x = 225.7 miles
The bearing will be 64° + α
α = tan⁻¹(165/154) = 47°
Bearing from starting position = 64 + 47 = 111°
In conclusion, the bearing and distance is determined using Pythagoras theorem.
Note that the complete question is:
From A to B a private plane flies 1.4 hours at 110 mph on a bearing of 64o. It turns at point B and continues another 1.5 hours at the same speed, but on a bearing of 154o to point C.
At the end of this time, how far is the plane from its starting point?
On what bearing(from due North) is the from its original location?
Learn more about bearing and distance at: https://brainly.com/question/24142612
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