The percent yield of the reaction that produced 0.350 mol HCI is 83.17%
How to determine the actual yield (in grams)
- Mole of HCl = 0.350 mole
- Molar mass of HCl = 36.5 g/mol
- Actual yield =?
Actual yield = 0.35 × 36.5
Actual yield = 12.775 g
How to determine the percentage yield
- Actual yield of HCl = 12.775 g
- Theoretical yield of HCl = 15.36 g
- Percentage yield =?
Percentage yield = (Actual / Theoretical) × 100
Percentage yield = (12.775 / 15.36) ×100
Percentage yield = 83.17%
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