Respuesta :
The temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr is 276 K or 3°C.
What is Charles's law?
Charles's law states that, "When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion".
V ∝ T
[tex]\frac{V}{T}=K[/tex]
Where,
V is the volume of the gas,
T is the temperature of the gas (measured in kelvins), and
K is a non-zero constant.
In two different states, an initial state 1 and a final state 2, the equation is,
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
Given data:
V1 = 11.2L
V2 = 13.3L
T2 = 55°C = 328K
By substituting the given data,
[tex]\frac{11.2}{T1}=\frac{13.3L}{328K}[/tex]
[tex]T1=\frac{11.2L/328K}{13.3L}[/tex]
∴T1 = 276K = 3°C
To learn more about Charles law: brainly.com/question/14842720
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