The correct option is D.
The three lowest-pitch tones generated by this pipe have wavelengths of = 2 L, L, 2 L/3
Measuring a wave's size from one peak to the next is all that is required. The wavelength is only the separation between the crests of the successive waves, if one thinks of a sound wave as being similar to a water wave.
The length of a pipe with an opening at either end and a length l is given by:
[tex]l=\frac{n \lambda}{2}[/tex]
or
[tex]\lambda=\frac{2 l}{n}[/tex]
Initial pitch tone: n = 1.
[tex]\lambda_{1}=2 l[/tex]
The first pitch tone has n = 2
[tex]\begin{aligned}\lambda_{2} &=\frac{2 l}{2} \\\lambda_{2} &=l\end{aligned}[/tex]
The initial pitch tone has n = 3.
[tex]\begin{aligned}&\lambda_{3}=\frac{2 l}{3} \\&\lambda_{3}=\frac{2 l}{3}\end{aligned}[/tex]
The three lowest-pitch tones generated by this pipe have wavelengths of 2 L, L, and 2 L/3, respectively.
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I understand that the question you are looking for is :
Consider a pipe of length L that is open at both ends. What are the wavelengths of the three lowest-pitch tones produced by this pipe?
Answer
A. 2L, L, L/2
B. 2L, L, L/2
C. 4L, 2L, L
D. 2L, L, 2L/3
E. 4L, 4L/3, 4L/5