Respuesta :

274 amu

Explanation:

Atomic weight of Na = 23

Atomic weight of Sio3 = 76

then,

molecular weight of Na2Sio3 = add 23*2 and 76*3

= 46 and 228

= 274 amu

Answer:

Answer:122 g/ mol

Answer:122 g/ molExplanation:

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compound

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses46+28+48 = 122g/mol