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What would the genotype of the parents need to be to produce a child that has a 50% chance of being born homozygous recessive and a 50% of being born heterozygous for Huntington’s disease? An empty Punnett square is provided to show your work

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One of the parents must be heterozygous while the other must be homzygous.

Huntington disease

Huntington's disease is an autosomal dominant disease. In other words, only one allele (dominant) is required for the disease to manifest.

In order to produce a child with a 50% chance of being homzygous for the disease, one of the parents must be heterozygous for the disease, while the other must be homzygous.

Assuming the allele for the disease is A(a).

                  AA    x    Aa

                AA   Aa   AA   Aa

Probability of AA = 2/4 or 50%

More on Huntington's disease can be found here: https://brainly.com/question/12572808

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