A man exerts a horizontal force of 123 N on a crate with a mass of 40.2 kg.

(A) If the crate doesn't move, what's the magnitude of the static friction force (in N)?
______N

(B) What is the minimum possible value of the coefficient of static friction between the crate and the floor? (Assume the crate remains stationary.)?

Question

contestada

Respuesta :

mickymike92 mickymike92 · Answer 1 · 2022-07-20T21:45:28+02:00

The magnitude of the static friction force = 123 N

The coefficient of static friction = 0.31

Static friction is the frictional force that must be overcome in other for a body to that moving over another.

Since the crate does not move, the magnitude of the static frictional force is equal to the applied force.

The magnitude of the static frictional force = 123 N

The coefficient of static friction = frictional force/normal reaction

The coefficient of static friction = 123/(40* 9.8)

The coefficient of static friction = 0.31

In conclusion, the static frictional force on the on the crate is equal to the applied force on the crate.

Learn more about static friction at: https://brainly.com/question/992319

#SPJ1