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In​ 2012, the population of a city was 6.38million. The exponential growth rate was 2.38​% per year.
​a) Find the exponential growth function.
​b) Estimate the population of the city in 2018.
​c) When will the population of the city be 9​million?
​d) Find the doubling time.
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Part 1
​a) The exponential growth function is ​P(t)

enter your response here​, where t is in terms of the number of years since 2012 and​ P(t) is the population in millions.

Respuesta :

The exponential growth function is P(t) = 6.38 million x (1.0238^t).

The population of the city in 2018 is 7.35 million.

The year the population would be 9 million is 14.46 years.

The doubling time is 29.12 years.

What is the exponential growth function?

FV = P (1 + r)^n

  • FV = Future population
  • P = Present population
  • R = rate of growth
  • N = number of years

6.38 million x (1.0238^t)

Population in 2018 = 6.38 million x (1.0238^6) = 7.35 million

Number of years when population would be 9 million : (In FV / PV) / r

(In 9 / 6.38) / 0.0238 = 14.46 years

Doubling time = In 2 / 0.0238 = 29.12 years

To learn more about exponential functions, please check: https://brainly.com/question/18760477

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