The number of half page advertisements that Michael purchased is 4 while the full page advertisements is 11.
The elimination approach involves taking one variable out of the system of linear equations by utilising addition or subtraction together with multiplication or division of the variable coefficients.
Let the number of half page ads be represented by h
Let the number of full page ads be represented by f.
Total number of advertisements = 15
h + f = 15 ....... (i)
h = 15 - f
Therefore, the system of equations to represent the situation will be:
60h + 100f = 1340 ........ (ii)
Put the value of h into equation (ii)
60(15 - f) + 100f = 1340
[tex]\Rightarrow[/tex] 900 - 60f + 100f = 1340
Collect like terms
100f-60f = 1340-900
[tex]\Rightarrow[/tex] 40f = 440
[tex]\Rightarrow[/tex] f = 11
The number of full-page advertisements that Michael purchased is 11.
Since h + f = 15
[tex]\Rightarrow[/tex] h + 11 = 15
[tex]\Rightarrow[/tex] h = 15 - 11
[tex]\Rightarrow[/tex] h = 4
The number of half page advertisements that Michael purchased is 5.
To learn more about advertisements from the given link
https://brainly.com/question/23884465
#SPJ4