Answer: [tex]y=-\frac{5}{3}x-1[/tex]
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals, so the slope of the line we want to find is -5/3.
Since the y-intercept is (0,-1), the equation is [tex]y=-\frac{5}{3}x-1[/tex]
The equation of the line passing through (0, -1) that is perpendicular to the line y=3/5x-3 is 5x + 3y + 3 = 0.
A line of the standard form y = mx + c , where m is the slope of the line and c is a y-intercept. Another way to express the equation for a line is in standard form.
Slope: A line's slope provides information on the steepness and direction of the line.
By figuring out the difference between both the coordinates of the two points, (x1,y1) and (x2,y2), it is simple to calculate the slope of such a straight line through them. The letter "m" denote the slope of the line.
Relation between slope of two perpendicular lines are-
Calculation for the equation of the line.
Consider the given equation;
y=3/5x-3 (compare this with the standard equation)
The slope 'm' is 3/5
Use the relation of slopes of two perpendicular line.
The slope of orthogonal line will be -1/m
Slope = -5/3
Put the slope in the slope point equation of line.
(y - y1) = m(x - x1)
where (x1,y1) = (0,-1)
Substitute the coordinates in the equation
y - (-1) = (-5/3)×(x - 0)
y + 1 = -5x/3
Further simplifying the equation,
5x + 3y +3 = 0
Therefore, the equation of the line passing through (0, -1) that is perpendicular to the line y=3/5x-3 is 5x + 3y +3 = 0.
To know more about standard form equation of the line, here
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