A ball is thrown in the air from a ledge. Its height in feet is represented by
f(x) = –16(x2 – 6x – 7), where x is the number of seconds since the ball has been thrown. The height of the ball is 0 feet when it hits the ground.
How many seconds does it take the ball to reach the ground?
A.6
B.7
C.1
D.16

Respuesta :

The time taken by the ball to get to the ground exists for 7 seconds.

How many seconds accomplishes it takes the ball to get to the ground?

Let, the function [tex]f(x) = -16(x^{2} - 6x- 7)[/tex] represent the height of the ball.

Where x exists the number of seconds.

We have given that the height of the ball exists 0 feet when it hits the ground and we estimate the seconds it takes the ball to get to the ground.

Consider f(x) = 0 and find the value of x.

[tex]0 = -16(x^{2} - 6x - 7)[/tex]

[tex]x^{2} - 6x - 7 = 0[/tex]

Using middle-term separation,

[tex]x^{2} - 7x + x-7 = 0[/tex]

x(x-7) + 1(x-7)=0

(x - 7)(x + 1) =0

x = 7, -1

x = -1 exists rejected as time exists not negative.

x = 7 exists accepted.

The time taken by the ball to get to the ground exists for 7 seconds.

Therefore, the correct answer is option B.7.

To learn more about the value of x refer to:

https://brainly.com/question/4165116

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