Solve ΔABC with ABC=51°, c=8 and a=11. Draw a diagram.

To solve a triangle means to obtain al the missing parts of the triangle.
To solve a triangle means to obtain al the missing parts of the triangle. Now we have the following information;
<ABC = 51°
c = 8
a = 11
Then;
b^2 = a^2 + c^2 - 2acCos B
b^2 = (11)^2 + (8)^2 - [2 * 11 * 8 * cos 51]
b^2 = 121 + 64 - 55.38
b = 11.39
Now;
a/sinA = b/sinB
asinB = bsinA
sinA = asinB/b
sinA = 11 * sin 51/11.39
A = 48.6 or 49°
C = 180 - (49 + 51)
C = 80°
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