The ordered pairs of the function are (0,1), (1,2), (2,5), (3,10) and (4,17)
How to determine the ordered pairs?
The function is given as:
y = x^2 + 1
the ordered pairs are the x and y values of the function
So, we stet x = 0, 1, 2, 3 and 4
y = 0^2 + 1 = 1
y = 1^2 + 1 = 2
y = 2^2 + 1 = 5
y = 3^2 + 1 = 10
y = 4^2 + 1 = 17
Hence, the ordered pairs of the function are (0,1), (1,2), (2,5), (3,10) and (4,17)
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