The metallurgist would need 46.875 lb of an alloy containing 30 % copper and 3.125 lb of an alloy containing 62 % copper to produce 50 lb of a third alloy.
In this question we must prepare a third alloy by using correct quantity of two alloys with different copper concentrations. Required weights can be determined by applying concept of weighted average:
(32/100) · (50 lb) = (30/100) · x + (62/100) · (50 - x)
32 · 50 = 30 · x + 62 · (50 - x)
32 · 50 = 30 · x + 62 · 50 - 62 · x
32 · x = 30 · 50
x = 46.875
The metallurgist would need 46.875 lb of an alloy containing 30 % copper and 3.125 lb of an alloy containing 62 % copper to produce 50 lb of a third alloy.
To learn more on weighted averages: https://brainly.com/question/18554478
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