contestada

Look at the rectangle and the square:

a rectangle pqrs and square lmno are drawn side by side. the length sr of the rectangle is labeled as 16 inches, and the width qr is labeled as 8 inches. the side lm of the square is labeled as 8 inches
ada says that the length of diagonal sq is two times the length of diagonal om.

is ada correct? justify your answer and show all your work. your work should state the theorem you used to find the lengths of the diagonals. (10 points) i will report you if you do it for the points!!!

Respuesta :

anuksha0456

Ada is incorrect, as the length of diagonal SQ is not two times the length of diagonal OM. The theorem used is the Pythagoras Theorem.

For Rectangle PQRS:-

By Pythagoras Theorem, in right triangle PQS,

SQ² = PQ² + PS²,

or, SQ² = 8² + 16² sq. inches,

or, SQ² = 64 + 256 sq. inches,

or, SQ = √320 sq. inches,

or, SQ = 8√5 inches.

Thus, the length of diagonal SQ, of rectangle PQRS is 8√5 inches.

For Square LMNO:-

By Pythagoras Theorem, in right triangle LMO,

OM² = LM² + LO²,

or, OM² = 8² + 8² sq. inches,

or, OM² = 64 + 64 sq. inches,

or, OM = √128 sq. inches,

or, OM = 8√2 inches.

Thus, the length of diagonal OM, of square LMNO is 8√2 inches.

We know that 2*OM ≠ SQ, as 2*8√2 ≈ 8√5.

Thus, Ada is incorrect, as the length of diagonal SQ is not two times the length of diagonal OM. The theorem used is the Pythagoras Theorem.

Learn more about the diagonal of square and rectangle at

https://brainly.com/question/22078692

#SPJ4

Ver imagen anuksha0456

Otras preguntas