The given center and point on the circle of (0,0) and (-5, 3), respectively
gives the equation of the circle as [tex]x^{2} +y^{2} =\sqrt{34}[/tex].
The general form of the equation of the circle is presented as follows
(x - h)² + (y - k)² = r²
Where,(h, k) is the center of the circle and r is the radius of the circle
Here (h, k) is centered about the origin and the radius of the circle
Radius of the circle = √[(-5-0)² + (3-0)²]
= √(25+9)
=√34.
The equation of a circle centered on the origin going through the point (-5,3)
[tex]x^{2} +y^{2} =\sqrt{34}[/tex]
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