1. given 5 mols of the compound below what is the mol ratio between the compound and O? Ca_4Si_2O_6(CO_3)(OH)_2
2. Given 2 mols of the compound in problem one what is the mol to mol ratio os Si?
3. Given 5 mols of the compound in problem one what is the mol to mol ratio between the compound and Ca?
4. Given 3.5 mols of the compound in problem one what is the mol to mol ratio between the compound and C?
5. in the reaction below give the mol to mol ratio between the underlined species
Pb(NO_3)_2(ap)+2KI(aq) -> PbI_2(s)+2KNO_3(aq)
underline underline

Respuesta :

The mole ratio of the compound and its constituent elements are as follows:

  1. The mole ratio between the compound and O is 5 : 22
  2. The mole ratio between the compound and Si is 2 : 4
  3. The mole ratio between the compound and Ca is 5 : 20
  4. The mole ratio between the compound and C is  1 : 1

What is mole ratio?

Mole ratio is the ratio of the moles of one or more elements or compounds to another.

The given compound is Ca₄Si₂O₆(CO₃)(OH)₂

Moles of oxygen present in 1 mole of compound = 11 moles

Moles of Si present in 1 mole of compound = 2 moles

Moles of Ca present in 1 mole of compound = 4 moles

Moles of C present in 1 mole of compound = 1 mole

  1. Given 5 moles of the compound below, the mole ratio between the compound and O is 5 : 22
  2. Given 2 moles of the compound below, the mole ratio between the compound and Si is 2 : 4
  3. Given 5 moles of the compound below, the mole ratio between the compound and Ca is 5 : 20
  4. Given 3.5 moles of the compound below, the mole ratio between the compound and C is  1 : 1

Given the equation of the reaction below;

  • Pb(NO₃)₂ (aq) + 2 KI (aq) --> PbI₂ (s) + 2 KNO₃ (aq)

the mole ratio of the reactants and products are as follows:

  • Pb(NO₃)₂ : 2 KI (aq) = 1 : 2
  • Pb(NO₃)₂ : PbI₂ (s0 = 1 : 1
  • Pb(NO₃)₂ : 2 KNO₃ (aq) = 1 : 2

In conclusion, the mole ratio of reaction is the ratio in which moles of the substances combine.

Learn more about mole ratio at: https://brainly.com/question/19099163

#SPJ1