Using the Factor Theorem, the expression 3x² + 2 is factored as follows:
[tex]3x^2 + 2 = (\sqrt{3}x + i\sqrt{2})((\sqrt{3}x - i\sqrt{2}))[/tex]
What is the Factor Theorem?
The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:
[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]
In which a is the leading coefficient.
In this problem, the expression is:
3x² + 2.
The roots are found as follows:
[tex]3x^2 + 2 = 0[/tex]
[tex]x^2 = -\frac{2}{3}[/tex]
[tex]x = \pm \sqrt{-\frac{2}{3}}[/tex]
[tex]x_1 = -i\sqrt{\frac{2}{3}}[/tex]
[tex]x_2 = i\sqrt{\frac{2}{3}}[/tex]
Hence the factored expression is:
[tex]3x^2 + 2 = \left(x + i\sqrt{\frac{2}{3}}\right)(x - 1\sqrt{\frac{2}{3}}\right) = (\sqrt{3}x + i\sqrt{2})((\sqrt{3}x - i\sqrt{2}))[/tex]
More can be learned about the Factor Theorem at https://brainly.com/question/24380382
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