Answer:
[tex]\sqrt{65}[/tex], so [?] = [65]
Step-by-step explanation:
This is a classic Pythagorean Theorem problem :)
We are given a right triangle with 2 sides, so all we have to do is plug it into the formula a² + b² = c², or in simple terms: the square of one side plus the square of the other equals the square of the hypotenuse.
line h is going to bisect the diameter of the circle (8) so one side will be 4. We're given 9 as our hypotenuse, so:
(4)² + (h)² = (9)².
16 + h² = 81
h² = 81 - 16, h² = 65, h = [tex]\sqrt{65}[/tex].
