contestada

At t=0s a small "upward" (positive y) pulse centered at x = 4.0 m is moving to the right on a string with fixed ends at x=0.0m and x = 13.0 m . The wave speed on the string is 3.5 m/s . At what time will the string next have the same appearance that it did at t=0s?

Respuesta :

onyebuchinnaji

The next time the string will have the same appearance that it did at t=0s is 2.29 s.

Frequency of the wave

v = fλ

f = v/λ

where;

  • λ is wavelength

half of the upward pulse is a quarter of wavelength = ¹/₄ x 4 m = 1 m

f = 3.5/1

f = 3.5 Hz

Time of motion when the pulse is at 4 m

t1 = 4/3.5 = 1.143 s

The next time the string will have the same appearance that it did at t=0s.

d = 4 m x 2 = 8 m

t2 = 8/3.5

t2 = 2.29 s

Thus, the next time the string will have the same appearance that it did at t=0s is 2.29 s.

Learn more about time of motion here: https://brainly.com/question/2364404

#SPJ1

Otras preguntas