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A firework is launched from the ground at a speed of 160 feet per second. It’s height after t seconds is given by the polynomial -16t^2+160t. What is the height of the firework after 4 seconds?

Respuesta :

alex255489
-16t^2+160t=0
16t^2=160t (Divided by 16)
t^2=10t (Divided by t)
t=10

Height
= Speed x Time
= 160 x 4
= 640 feet

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