The decomposition of H2O2 is a first-order reaction given by the formula: Rate = k [H2O2]1. How would the reaction rate be affected if the H2O2 concentration were double its original value?

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19-07-2022
Physics

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The decomposition of H2O2 is a first-order reaction given by the formula: Rate = k [H2O2]1. How would the reaction rate be affected if the H2O2 concentration were double its original value?

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Nandhitha1098 Nandhitha1098 · Answer 1 · 2022-07-28T10:38:58+02:00

Answer: The decomposition of H₂O₂ is a first-order reaction. Then, the reaction rate will be 2 times the original rate, if we double its concentration value.

Explanation: To find the answer, we need to know about the decomposition of H₂O₂.

What is the rate of reaction, if we double the concentration of H₂O₂?

We have the equation of decomposition of H₂O₂ as,

2H₂O₂→ 2 H₂O+ O₂

We have given that, the equation of reaction rate of the first order reaction as,

Rate = k [H₂O₂]1

As we know that the equation of reaction rate is,

Rate = rate constant × concentration of [H₂O₂]

Thus, by comparing both the equations, we get,

rate constant=k and the concentration of [H₂O₂] = 1[H₂O₂].

Given that the concentration is doubled. Then the expression for rate will be,

Rate = 2k [H₂O₂].

Thus, we can conclude that the rate of reaction will be 2 times the initial rate if we double the concentration.

Learn more about the decomposition of H₂O₂ here:

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aadildhillon023 aadildhillon023 · Answer 2 · 2022-07-30T15:57:49+02:00

If we double the concentration value, the reaction rate will be twice as fast as before.

In order to determine the solution, we must understand how H2O2 breaks down.

If we double the concentration of H2O2, what will happen to the reaction rate?

The formula for the breakdown of H2O2 is,

2H₂O₂→ 2 H₂O+ O₂

We have provided the first order reaction's reaction rate equation as,

Rate = [H2O2] k

As we are aware, the reaction rate equation is

Rate = rate constant × [H2O2] concentration

As a result, by comparing the two equations, we obtain, rate constant is k, and the [H2O2] concentration is 1 [H2O2].

The concentration has doubled as a result. Afterward, the rate expression will be,

Rate = [H2O2] 2k.

As a result, we can infer that doubling the concentration will cause the reaction rate to double.

Learn more about how H2O2 breaks down here:

https://brainly.com/question/28047273

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