What is the approximate area of the triangle below?
95 degrees 35 degrees 14cm.

By utilizing the law of the sines and Heron's formula, we find that the approximate area of the triangle is approximately 73.1 square centimeters. (Correct choice: A)
Prior to using Heron's formula, we must find the lengths of the missing sides by law of the sines:
A = 180° - 95° - 35°
A = 50°
[tex]b = 14\,cm \times \frac{\sin 35^{\circ}}{\sin 50^{\circ}}[/tex]
b ≈ 10.483 cm
[tex]c = 14\,cm \times \frac{\sin 95^{\circ}}{\sin 50^{\circ}}[/tex]
c ≈ 18.206 cm
Now, we proceed to calculate the area of the triangle:
s = 0.5 · (14 cm + 10.483 cm + 18.206 cm)
s = 21.345 cm
[tex]A = \sqrt{(21.345\, cm) \cdot (21.345\, cm - 14\,cm)\cdot (21.345\, cm - 10.483\,cm)\cdot (21.345\,cm - 18.206\,cm)}[/tex]
A ≈ 73.113 cm²
By utilizing the law of the sines and Heron's formula, we find that the approximate area of the triangle is approximately 73.1 square centimeters. (Correct choice: A)
To learn more on triangles: https://brainly.com/question/2773823
#SPJ1