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On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded.
Which linear inequality is represented by the graph?

y ≤ One-thirdx − 1
y ≥ One-thirdx − 1
y < 3x − 1
y > 3x − 1

Respuesta :

facundo3141592

The graphed inequality is:

[tex]y \geq \frac{1}{3}*x - 1[/tex]

Which linear inequality is represented by the graph?

We know that the line is solid, and the region above and to the left is shaded, then the inequality is of the form:

y  ≥ line.

Now we need to get the linear equation.

It is of the form;

y = a*x + b

Where a is the slope and b is the y-intercept. Because it passes through (0, -1), we know that the y-intercept is -1.

And knowing that the line passes through (0, -1) and (3, 0), the slope is:

[tex]a = \frac{- 1 - 0}{0 - 3} = \frac{1}{3}[/tex]

Then the inequality is:

[tex]y \geq \frac{1}{3}*x - 1[/tex]

If you want to learn more about inequalities:

https://brainly.com/question/18881247

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