The new pressure changed relative to the original by a factor of 8/3.
What is the change in the pressure?
Using the ideal gas equation;
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
P1 = nRT/V
P2 = 4n * R * 2T/3V
Hence;
P2/P1 = 4n * R * 2T/3V ÷ nRT/V
P2/P1 = 4n * R * 2T/3V * V/nRT
P2/P1 =4 * 2/3
= 8/3
Learn more about ideal gas law:https://brainly.com/question/13821925
#SPJ1
