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I don't understand how it gets the result [tex]28b_{2}[/tex] and [tex]b_{2}^{2}[/tex] in the fourth equation.

I dont understand how it gets the result tex28b2tex and texb22tex in the fourth equation class=
I dont understand how it gets the result tex28b2tex and texb22tex in the fourth equation class=

Respuesta :

Answer + Step-by-step explanation:

your question is about equation 4 :

[tex]b_{1}=14-b_{2}[/tex]

Then

[tex]\left( b_{1}\right)^{2} =\left( 14-b_{2}\right)^{2} \ \text{(this is a special product )}[/tex]

Then

[tex]\left( b_{1}\right)^{2} =14^{2}-2\times 14 \times b_{2}+ (b_2)^2[/tex]

Then

[tex]\left( b_{1}\right)^{2} =196-28 b_{2}+ (b_2)^2[/tex]