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If P = (-3,-2) and Q = (1, 6) are the endpoints of the diameter of a circle, find the equation of the circle.


(x +?)^2 + (y - ?)^2 = ?

Respuesta :

mariollosa1234

Answer:

(x+1)²+(y-2)²= 20

Step-by-step explanation:

P = (-3,-2)

Q = (1, 6)

Center (h, k)

C = ((-3+1)/2 , (-2+6)/2)

C = (-2/2 , 4/2)

C = (-1 , 2)

Radius = Distance from the center to point Q

R = √((1-(-1))² + (6-(2))²)

R = √((2)² + (4)²)

R = √(4+ 16)

R = √20

Equation

(x-h)²+(y-k)²= R²

(x-(-1))²+(y-2)²= (√20)²

(x+1)²+(y-2)²= 20

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