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What happens to a 8 L volume of gas as you love a pressure of 3 atm to 4 atm? Use the correct gas law to determine the new volume

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Medunno13

Assuming pressure is held constant,

[tex]\frac{8}{3}=\frac{V_{2}}{4}\\\\V_{2}=4\left(\frac{8}{3} \right) \approx \boxed{10.7 \text{ L}}[/tex]

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